Posted by **Embraced** on Saturday, January 21, 2012 at 6:42pm.

FInd the 5th term of (x2y)^10

- ALG 2 -
**drwls**, Saturday, January 21, 2012 at 8:58pm
There is only one term.

It is x^20*y^10

Did it really ask for the fifth term of (x^2 + y)^10 ?

That would depend upon the order that the terms are listed

- ALG 2 -
**Steve**, Sunday, January 22, 2012 at 11:09am
Taking a look at the previous posting plug your values into row 10 of Pascal's triangle:

1 10 45 120 210 252 210 120 45 10 1

Watch out, because the terms involve x^2 and not just x:

(x^2)^10 + 10(x^2)^9 y + ...

The 5th term is 210(x^2)^6y^4 = 210 x^12 y^4

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