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Posted by on Saturday, January 21, 2012 at 6:42pm.

FInd the 5th term of (x2y)^10

  • ALG 2 - , Saturday, January 21, 2012 at 8:58pm

    There is only one term.
    It is x^20*y^10

    Did it really ask for the fifth term of (x^2 + y)^10 ?

    That would depend upon the order that the terms are listed

  • ALG 2 - , Sunday, January 22, 2012 at 11:09am

    Taking a look at the previous posting plug your values into row 10 of Pascal's triangle:

    1 10 45 120 210 252 210 120 45 10 1

    Watch out, because the terms involve x^2 and not just x:

    (x^2)^10 + 10(x^2)^9 y + ...

    The 5th term is 210(x^2)^6y^4 = 210 x^12 y^4

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