A dominant gene A produces wire-haired texture in dogs. Its recessive aamllele a produced smooth hair. Cross the heterozygous wire-haired dog with homozygous smooth-haired dog. List the genotype and phenotype ratios of all the possible offspring.
Parents genotypes are Ws and ss. Use a Punnett square.
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To determine the genotype and phenotype ratios of the possible offspring, we need to understand the laws of inheritance and use a Punnett square.
First, let's define the genotypes of the parent dogs:
Heterozygous wire-haired dog: Aa (genotype)
Homozygous smooth-haired dog: aa (genotype)
Now, let's create a Punnett square to determine the possible genotypes and phenotypes of the offspring:
| A | a |
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A | AA | Aa |
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a | Aa | aa |
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From the Punnett square, we can see that there are two possible genotypes for the offspring: AA and Aa. The genotype aa is not possible because it requires both parents to carry the recessive allele, which is not the case in this cross.
Let's determine the phenotype ratios based on the genotypes:
1. Genotype AA: This genotype corresponds to wire-haired texture.
2. Genotype Aa: This genotype also corresponds to wire-haired texture, as the dominant allele A produces this trait.
Therefore, all the possible offspring will have wire-haired texture.
To summarize:
- Genotype ratio: All possible offspring will have the genotype Aa (50%) or AA (50%).
- Phenotype ratio: All possible offspring will have the wire-haired phenotype (100%).