What is the specific heat of a metal if 7.74 x 103 J of energy is required to warm a 75.0 g sample of the metal from 10 °C to 125 °C?
To find the specific heat of a metal, we can use the formula:
q = mcΔT
Where:
q is the amount of heat energy transferred
m is the mass of the metal sample
c is the specific heat capacity of the metal
ΔT is the change in temperature
In this case, we are given:
q = 7.74 x 10^3 J
m = 75.0 g
ΔT = 125 °C - 10 °C = 115 °C
Plugging these values into the formula, we get:
7.74 x 10^3 J = (75.0 g)(c)(115 °C)
Now, we can solve for c:
c = (7.74 x 10^3 J) / (75.0 g)(115 °C)
c ≈ 0.0934 J/g°C
Therefore, the specific heat of this metal is approximately 0.0934 J/g°C.