Post a New Question

Pre-Calc B

posted by on .

How do I find zeros on a graph of a cubic function? I can tell that two of the zeros are -4 and 3 because they show on the graph, but how do I find the other?

  • Pre-Calc B - ,

    y = a x ^ 3 + b x ^ 2 + c x + d = a ( x - x1 ) ( x - x2 ) ( x - x3)

    y = a [ x - ( - 4 ) ] ( x - 3 ) ( x - x3 )


    y = a ( x + 4 ) ( x - 3 ) ( x - x3 )

    You must know 4 points on graph to solve this equation.

    Maybe your function has a double root (that is, one of the zeroes has a multiplicity of two).

    In this case :

    y = a ( x + 4 ) ( x + 4 ) ( x - 3 )

    OR

    y = a ( x + 4 ) ( x - 3 ) ( x - 3 )

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question