Posted by mark on Friday, January 20, 2012 at 10:14pm.
I assume you know how to find the empirical formula since you obtained the right answer for C5H10O. The molecular formula is 86.13/empirical formula mass = x where is is the multiplier to be used on the empirical formula.
Just suppose the empirical formula mass is 42. Then 86.13/42 =2.051 which you would round to 2.0 and the molecular formula would be (CxHyOz)2 which will make the molecular formula
C2xH2yO2z
Post your work if you run into trouble.
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