Homework Help: Physics

Posted by Kayla on Friday, January 20, 2012 at 9:27pm.

A skateboarder, starting from rest, rolls down a 12.5-m ramp. When she arrives at the bottom of the ramp her speed is 6.45 m/s.
(a) Determine the magnitude of her acceleration, assumed to be constant.

Physics - drwls, Saturday, January 21, 2012 at 8:24am
V = sqrt(2 a X) applies when the starting velocity is zero. , therefore

a = V^2/(2 X)= 1.664 m/s^2

Here's how you can derive it (if you can't remember it).

Average velocity = V/2
Time T = X/(V/2) = 2 X/V
Acceleration a = V/T = V^2/(2 X)

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