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April 19, 2014

April 19, 2014

Posted by **mark** on Friday, January 20, 2012 at 9:04pm.

A 1.208 g sample of a compound containing C, H, and O was burned to produce 2.561 g CO2 and 0.3930 g H2O. Calculate the empirical formula of the compound.

I always get stuck when it comes to finding the subscript for this compound.

- chemistry -
**DrBob222**, Friday, January 20, 2012 at 9:44pmConvert 2.561g CO2 to g C. Easiest done by 2.561 x (atomic mass C/molar mass CO2).

Convert 0.3930g H2O to g hydrogen. Easiest done by 0.3930 x (2*atomic mass H/molar mass H2O).

Then g O = 1.208 - g C - g H

Now convert g C, H, and O to moles.

moles = grams/molar mass.

Find the ratio of the elements to each other using whole numbers with the smallest being 1.00. That is easiest done by dividing the smallest number by itself; then divide the other mole amounts by the same small number.

If you have trouble, post your work and I can help guide you through it. Be sure to explain what you don't understand about the next step.

- chemistry -
**mark**, Friday, January 20, 2012 at 10:08pmI ended up with C_2.809 H_2.106 O_1

so would that be C_3 H_2 O?

- chemistry -
**DrBob222**, Friday, January 20, 2012 at 10:39pmI would round that way BUT I didn't get those numbers. I ended up with 1.99 for C, 1.496 for H, 1.00 for O which rounds to C2H1.5O but that in small whole numbers is C4H3O2 if I didn't make a math error. Look over your work to see if you can find an error; post your work and I'll look for an error if you wish.

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