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April 24, 2014

April 24, 2014

Posted by **Anon** on Friday, January 20, 2012 at 7:24pm.

x-axis.

The ray intersects the fixed line y = 2 at point A. From A you measure out 7 more units to point P on the graph of the conchoid. The bottom part is formed when the ray is in Quadrants III and IV and you measure 7 units from where the line containing the ray intersects the fixed line.

The parametric equation for x has two parts, one for the segment from the origin to the point on the x-axis below point A, the other from there to the point on the x-axis below point P. Write an equation for x as a function of t.

x = 2 t + t

Write the parametric equation for y as a function of t. It, too, will have two parts.

y = + t

The Cartesian equation of this conchoid is

(x^2 + y^2)(y - 2)^2 = 49y^2

Verify that this equation is correct by calculating the values of x if y is 8 and showing that the points really are on the conchoid.

(Round to the nearest hundredth.)

- Precalculus -
**Damon**, Friday, January 20, 2012 at 7:29pmNow this is getting out of control. You try.

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