posted by Deborah on .
Suppose 24.9 grams of copper (II) nitrate is dissolved in 200. milliliters of a 0.70 moles/liter aqueous solution of sodium chromate.
Calculate the final molarity of nitrate anion in the solution.
24.9g/molar mass Cu(NO3)2 = mols Cu(NO3)2.
There are two mols NO3^- for each mole Cu(NO3)2.
Then M = mols/L soln = mols/0.200L = ?