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December 18, 2014

December 18, 2014

Posted by **Anon** on Friday, January 20, 2012 at 5:08pm.

I think it's -5

Find the two complex zeros of g(x):

- Precalc -
**Anon**, Friday, January 20, 2012 at 5:09pm*(x + 5)(x^2 - 6x + 13)

- Precalc -
**Reiny**, Friday, January 20, 2012 at 6:24pmcorrect for real root x = -5

for complex:

x^2 - 6x + 13 = 0

x =(6 ± √-16)/2

= (6 ± 4i)/2

= 3 ± 2i

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