Posted by Anon on Friday, January 20, 2012 at 1:54pm.
You must be studying the ellipse, therefore, must be familiar with the properties of an ellipse such as the a and b values
Can we assume that Mars is at one of the focal points of the elliptical path?
2a = 156+128 = 284
a = 142
c = 142-128 = 14
Calculate major radius etc, as defined in your text.
eccentricity = 14/142 = .0986
also b^2 + c^2 = a^2
b^2 + 14^2 = 142^2
b^2 = 19968
b = √19968 = 141.308
equation:
x^2 / 142^2 + y^2 / 141.308^2 = 1
at equinox, x = 14
14^2/142^2 + y^2/141.308^2 = 1
y^2 / 141.308^2 = .990279706
y^2 = 19773.905
y = 140.62
So it is 140.62 million miles from the sun.
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