Posted by **Anon** on Friday, January 20, 2012 at 12:18pm.

A geometric series has t1 = 3 and r = 2. If tn = 96. What does n equal in this problem?

What is the special name given to the terms between 3 and 96 in this problem?

- Precalculus -
**Reiny**, Friday, January 20, 2012 at 12:34pm
You are given that a = 3 and r = 2

so

tn = ar^(n-1)

96 = 3(2^(n-1)

32 = 2^(n-1)

2^5 = 2^(n-1)

n-1 = 5

n = 6

3, 6, 12, 24, 48, 96

terms in between are called geometric means

- Precalculus -
**Anon**, Friday, January 20, 2012 at 12:56pm
Thanks!

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