Posted by Anon on Friday, January 20, 2012 at 12:18pm.
A geometric series has t1 = 3 and r = 2. If tn = 96. What does n equal in this problem?
What is the special name given to the terms between 3 and 96 in this problem?

Precalculus  Reiny, Friday, January 20, 2012 at 12:34pm
You are given that a = 3 and r = 2
so
tn = ar^(n1)
96 = 3(2^(n1)
32 = 2^(n1)
2^5 = 2^(n1)
n1 = 5
n = 6
3, 6, 12, 24, 48, 96
terms in between are called geometric means

Precalculus  Anon, Friday, January 20, 2012 at 12:56pm
Thanks!
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