Posted by Isabella on .
An electric field of intensity 4.27 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the following conditions are true.
(a) The plane is parallel to the yz-plane.
(b) The plane is parallel to the xy-plane.
(c) The plane contains the y-axis, and its normal makes an angle of 41.7° with the x-axis.
(a) In this case, the E field is perpendicular to the plane of the surface. Multiply the field strength by the area.
(b) In this case, the E field is parallel to the surface and the flux is zero.
(c) E*(Area)*(cos41.7) = ?