Posted by chrystabelle on Friday, January 20, 2012 at 3:22am.
DIFFERENTIATE FROM FIRST PRINCIPLES
(I)3X
(ii)X^2+2X+3
(iii)1/x^2

maths  Reiny, Friday, January 20, 2012 at 10:06am
I will do the middle one, you do others, looks like an assignment.
f(x) = x^2  2x + 3
dy/dx = LIM [ f(x+h)  f(x) ]/h as h> 0
f(x+h) = (x+h)^2 + 2(x+h) + 3
= x^2 + 2xh + h^2 + 2x + 2h + 3
Lim [ f(x+h)  f(x) ]/h
= lim (x^2 + 2xh + h^2 + 2x + 2h + 3  (x^2 + 2x + 3)/h
= lim (2xh + h^2 + 2h)/h
= lim 2x + h + 2
= 2x + 2
(each of the "lim" has h> 2 under it)
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