Posted by Grace on Friday, January 20, 2012 at 12:44am.
I don't know which author you use, but focal radius can be defined in more than one way
http://www.mathwords.com/f/focal_radius.htm
for yours,
a = 5, b = 3
your ellipse will be horizontal, and
b^2 + c^2 = a^2
9+c^2 = 25
c^2 = 16
c = 4
eccentricity = c/a = 4/5 = .8
parametric equations:
x-2 = 5coss t ---> x = 5cost + 2
y-4 = 3sin t ----> y = 3sint + 4
original:
(x-2)^2 /25 + (y-4)^2 / 9 = 1
multiply by 225
9(x-2)^2 + 25(y-4)^2 = 225
9(x^2 - 4x + 4) + 25(y^2 - 8y + 16) = 225
I am sure you can finish it.
Related Questions
Precalculus - I don't even how to go about this.... Mars is in an elliptical...
Calculus - find the equation for an ellipse that satisfies the following ...
Geometry - For an ellipse, one focus is (0,0), one vertex is (2,0), and the ...
Precalc - A hyperbola has this Cartesian equation: -((x-2)/5)^2 + ((y+1)/3)^2 = ...
Physics - I have to find the eccentricity of an elliptical orbit with one focus...
Math - This question makes reference to an orthonormal basis (i,j), and an ...
maths - Given that the ellipse x^2/a^2 + y^2/b^2 =1 has foci at(+/-ae,0)where e ...
geometry - The area of an ellipse in the form (x*x/a*a)+(y*y)/(b*b)=1 is A=3.14*...
algebra - 1)Write an equation for an ellipse if the endpoints of the major axis ...
calculus - (a) Modifying the parametric equations of a unit circle, find ...
For Further Reading
