Posted by **Anonymous** on Thursday, January 19, 2012 at 10:33pm.

the sides of a triangle have lengths 4x+1, 2x+1 and 6x-1. if the lengths of the longest side is 6x-1, what values of x make the triangle obtuse?

- geometry -
**Reiny**, Thursday, January 19, 2012 at 11:52pm
(6x-1)^2 > (4x+1)^2 + (2x+1)^2 ,

36x^2 - 12x + 1 = 16x^2 + 8x + 1 + 4x^2 + 4x + 1

6x^2 - 24x -1 > 0

suppose we solve the corresponding equation

6x^2 - 24x -1 = 0

x = (24 ± √600)/12

=(24 ± 10√6)/24

= (12 ± 5√6)/12 = appr 2.0206 or a negative

but clearly 6x-1 > 0

x > 1/6

so it is obtuse for x > 2.0206

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