Posted by Jason on .
A ball is thrown from a cliff upward with a speed of 20 m/s, the angle is 33 degrees and the ball hits the ground 9.2 seconds later, how high is the cliff to the nearest meter?
Is the 33 degrees with respect to vertical or horizontal? You need the initial vertical velocity component to answer the question. Call it Vyo.
Vyo*t - (g/2) t^2 = -H
Solve for the cliff height H. You know what t is: 9.2 s.