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July 23, 2014

July 23, 2014

Posted by **Ella** on Thursday, January 19, 2012 at 7:42pm.

~Please help me and provide an explanation for your answer.

Please and thank you!

- Algebra -
**Reiny**, Thursday, January 19, 2012 at 8:12pmnumber of hamburgers ---- x

number of turkeyburgs --- 21-x

weight of hamburgers = (1/3)x

weight of turkeyburgs = (1/4)(21-x

so (1/3)x = (1/4)(21-x)

times 12 , the LCD

4x = 3(21-x)

4x = 63-3x

7x = 63

x = 9

so 9 hamburgers and 12 turkeyb's

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