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Electrical Engineering
Circuit Analysis
measure resistance with a multimeter in a circuit is the power going to be off or on
i think ON
1 answer
I think off. You will be applying a small voltage across the resistance to make the measurement.
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Similar Questions
measure resistance with a multimeter in a circuit is the power going to be off or on
i think ON
Top answer:
To measure resistance with a multimeter, the circuit must be powered off. The reason for this is
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a series RLC circuit has a peak current of 4 A with a frequency of 23 kHz. if the resistance of the circuit is 60 kohm, the
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wouldn't it be i^2 R? i is rms current, or .70Peak, so i^2=Ipeak/2
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a series RLC circuit has a peak current of 4 A with a frequency of 23 kHz. if the resistance of the circuit is 60 kohm, the
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I = 0.707*4 = 2.828A rms. P = I^2*R = (2.828)^2 * 60 = 480 kW.
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a series RLC circuit has a peak current of 4 A with a frequency of 23 kHz. if the resistance of the circuit is 60 kohm, the
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See previous post.
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a series RLC circuit has a peak current of 4 A with a frequency of 23 kHz. if the resistance of the circuit is 60 kohm, the
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I = 0.707 * 4A = 2.83A,rms. P = I^2 * R = (2.83)^2 * 60,000 = Answer in Watts.
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I'm not sure how tutors here can be of much help without the diagram for this one. Though I suppose
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