Posted by **Micheal** on Thursday, January 19, 2012 at 3:34pm.

An 80 kg person decides to jump off the back end of a 30 kg canoe. His friend measures the speed of the canoe after he jumps to be 0.8 m/s. The canoe was initially at rest. What rule would I use to find the speed of the person who jumped?

- Science -
**Steve**, Thursday, January 19, 2012 at 4:09pm
initially there was 0 momentum. That momentum is conserved. So, assigning the canoe's direction as negative,

30*(-.8) + 80*v = 0

80v = 24

v = +.3m/s

- Science -
**bobpursley**, Thursday, January 19, 2012 at 4:10pm
conservation of momentum

initial mometum= final momentum

(80+30)Vc=30*.8-80*V

but Vc=0, the canoe was not moving initially. Solve for V

## Answer This Question

## Related Questions

- Physics - two groups of paddlers meet in the middle of a lake. after a brief ...
- Physics - Two groups of canoeists meet in the middle of a lake. After a brief ...
- physics - A man with a mass of 58 kg stands up in a 69-kg canoe of length 4.0 m ...
- physics - A man with a mass of 62 kg stands up in a 64-kg canoe of length 4.0 m ...
- physics - A man with a mass of 50 kg stands up in a 66-kg canoe of length 4.0 m ...
- physics - A man with a mass of 52 kg stands up in a 66-kg canoe of length 4.0 m ...
- Physics - A man with a mass of 65 kg stands up in a 64-kg canoe of length 4.0 m ...
- physics - A man with a mass of 64.1 kg stands up in a 61-kg canoe of length 4.00...
- itu - A man with a mass of 64.1 kg stands up in a 61-kg canoe of length 4.00 m ...
- Physics - A 9.6 kg dog takes a nap in a canoe and wakes up to find the canoe has...

More Related Questions