Posted by **Micheal** on Thursday, January 19, 2012 at 3:34pm.

An 80 kg person decides to jump off the back end of a 30 kg canoe. His friend measures the speed of the canoe after he jumps to be 0.8 m/s. The canoe was initially at rest. What rule would I use to find the speed of the person who jumped?

- Science -
**Steve**, Thursday, January 19, 2012 at 4:09pm
initially there was 0 momentum. That momentum is conserved. So, assigning the canoe's direction as negative,

30*(-.8) + 80*v = 0

80v = 24

v = +.3m/s

- Science -
**bobpursley**, Thursday, January 19, 2012 at 4:10pm
conservation of momentum

initial mometum= final momentum

(80+30)Vc=30*.8-80*V

but Vc=0, the canoe was not moving initially. Solve for V

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