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October 31, 2014

October 31, 2014

Posted by **Misty** on Thursday, January 19, 2012 at 1:55pm.

The cost of gasoline per gallon in 1989 is $2.39. In 1995, the cost of gas per gallon is $2.69. In what year will the cost of gas be $2.89?

Mr. Jenssen's car decreased in value at a constant rate at the start of each successive year. The casr was worth $11,000 in 2003 and $9,600 in 2007. When the car was worth $8,900, he sold it, In what year did Mr. Jessen sell the car?

- Math( 8th) Rate of change -
**DrBob222**, Thursday, January 19, 2012 at 2:29pmProblems 1 and 2$2.69-$2.39 don't make it clear how many years but I will assume we subtract 2006-2003 = 3 years.

So the $200 has grown by $15 in the 3 year or $5/year.

Let x = number of years

200 + 0.05x = 230

Solve for x and add to year 2003.

$2.69-2.39 = 0.30 increase in 6 years (1995-1989) which is 0.05/year.

Let x = number of years.

2.39 + 0.05*x = 2.89

x = (2.89-2.39)/0.05 = 10 years and add that to 1989.

Problem 3 states how the years are to be counted; i.e., at the start of each year. The car is worth $11,000 at the start of 2003 and at the start of 2007 it was worth %9,600. That's 4 years so it is decreasing at the rate of $(11,000-9600)/4 = $350/year.

Let x = number of years.

11,000 - 350x = 8,900

x = 6 years; add that to 2003 so he must have sold the car at the start of the year

2009. Check my work.

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