posted by Deborah on .
chemistry student weighs out 0.123 grams of chloroacetic acid (HCH2ClCO2) into a 250. milliliter volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1200 moles/liter NaOH solution.
Calculate the volume of NaOH solution the student will need to add to reach the equivalence point.
moles chloroacetic acid = M x L
moles acid = moles NaOH
M NaOH = moles NaOH/L NaOH. You have M NaOH and M NaOH, solve for L NaOH and convert to mL if you wish.