Posted by **Grace** on Thursday, January 19, 2012 at 3:09am.

The figure shows a 10 x 10 square centered at the origin. The darker-shaded square is the image of this square, dilated by a factor of 0.8 and rotated about the origin by exactly the number of degrees, , so that its corners touch the sides of the parent square. The corners of the rotated square divide the sides of the 10 x 10 square into segments of length a and b.

Use the fact that a and b add up to 10 to find the value of theta.

- Precalc -
**drwls**, Thursday, January 19, 2012 at 6:28am
Not without the figure. I cannot visualize the situation from your verbal description. Perhaps another teacher can.

- Precalc -
**Steve**, Thursday, January 19, 2012 at 11:09am
You end up with a rotated square of side 8, surrounded by 4 right triangles of sides x and 10-x.

x^2 + (10-x)^2 = 64

x^2 + 100 - 20x + x^2 = 64

2x^2 - 20x + 36 = 0

x^2 - 10x + 18 = 0

x = 5 ± √7 = 2.35 or 7.65

if we let x be the smaller value, then

tanθ = 2.35/7.65 = 0.307

θ = 17°

- Precalc -
**Grace**, Thursday, January 19, 2012 at 1:03pm
Thank you so so so much! I've been stuck on this for hours!

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