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January 30, 2015

January 30, 2015

Posted by **i need your help please :(** on Wednesday, January 18, 2012 at 11:07pm.

- physics -
**drwls**, Thursday, January 19, 2012 at 1:23amYou would have received help earlier if you had listed the subject correctly. It is not "I need help please". If you also want that to be your name, that your choice.

For a quick answer, set the initial kinetic energy at the bottom equal to the work done against friction, after traveling a horizontal distance X, where it stops.

(1/2) M Vo^2 = M g *(0.030)*X

Vo s the initial velocity at the foot of the hill.

M cancels out, and does not matter. Solve for X.

X = Vo^2/(2*g *.03)

Since you are using feet as the length unit, g = 32.2 ft^2/s

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