Tuesday

July 22, 2014

July 22, 2014

Posted by **Shreya** on Wednesday, January 18, 2012 at 10:09pm.

- math-calculus -
**Steve**, Thursday, January 19, 2012 at 5:06amif 2x-3 >= 0 then you have

2x-3 - |2x-5| = 0

Now, if 2x-5 >= 0, that gives

2x-3 - (2x-5) = 0

2 = 0

no good

If 2x-5 < 0 you have

2x-3 - -(2x-5) = 0

2x-3 + 2x-5 = 0

4x - 8 = 0

x = 2

since x=2 satisfies both conditions

2x-56 < 0 and 2x-3 >= 0, it's a solution.

Work through the other possibilities to find that x=2 is the only solution.

Makes sense, since the graphs of the two absolute values are v-shaped with equal slopes, so they intersect in only one point.

**Related Questions**

math-calculus - |2x-3|-|2x+5| = 0 i please need helps with this.

math - I need help finding the missing length of a triangle. We need help to ...

ict yr 8 - please could someone help me. i need to find cinemas in my local area...

ks3 textiles - i need help with my textile homework. i need to say why silk is ...

Math (Calculus AB) - An equation to the graph of y=x^3+3x^2+2 at its point of ...

Calculus Need of Urgent help - find the indicated limits, if they exist. 1. lim...

Calculus Please Need Urgent3 :/ - Find the derivative of the following function ...

math - I need to see how to arrange 8-1/5y=10x to mx+b form Is it -1/5y=10x-8? I...

calculus - Please help. I need ( with details) how to differentiate with the ...

math - I need help with the math textbook stretching and Shrinking page 89, ...