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December 22, 2014

December 22, 2014

Posted by **Shreya** on Wednesday, January 18, 2012 at 10:09pm.

- math-calculus -
**Steve**, Thursday, January 19, 2012 at 5:06amif 2x-3 >= 0 then you have

2x-3 - |2x-5| = 0

Now, if 2x-5 >= 0, that gives

2x-3 - (2x-5) = 0

2 = 0

no good

If 2x-5 < 0 you have

2x-3 - -(2x-5) = 0

2x-3 + 2x-5 = 0

4x - 8 = 0

x = 2

since x=2 satisfies both conditions

2x-56 < 0 and 2x-3 >= 0, it's a solution.

Work through the other possibilities to find that x=2 is the only solution.

Makes sense, since the graphs of the two absolute values are v-shaped with equal slopes, so they intersect in only one point.

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