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April 18, 2014

April 18, 2014

Posted by **Shreya** on Wednesday, January 18, 2012 at 9:40pm.

- math-calculus -
**math1**, Wednesday, January 18, 2012 at 10:10pmyou cannot solve it since you cant square root a negative number... unless -2x was positive 2x.

- math-calculus -
**Shreya**, Wednesday, January 18, 2012 at 10:41pmsorry i missing part of question whole question be |x^2-2x-6| = 4. and answer have to be 1+-sqrt3, 1+-sqrt11 i just not get how to get this.

- math-calculus -
**Steve**, Thursday, January 19, 2012 at 10:02amf(x) = x^2 - 2x - 6 has roots 1±√7 = -1.65,3.65

Between the roots, f(x) < 0 and we have

-(x^2-2x-6) = 4

x^2 - 2x - 2 = 0

x = 1±√3

both those values are in the interval, so they're ok as solutions

Outside that interval,

x^2-2x-6 = 4

x^2 - 2x - 10 = 0

x = 1±√11

both those values are outside the interval, so they're ok as solutions

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