What is the molarity if 750. mL of a solution containing 332.5g of copper (II) sulfate
moles CuSO4 = grams/molar mass
M = moles/L soln
To find the molarity, we need to use the formula:
Molarity = moles of solute / volume of solution (in liters)
Step 1: Convert the given mass of copper (II) sulfate to moles.
In order to convert grams to moles, we need to know the molar mass of copper (II) sulfate. The formula for copper (II) sulfate is CuSO4, which consists of one copper atom, one sulfur atom, and four oxygen atoms.
The molar masses are:
Copper (Cu): 63.55 g/mol
Sulfur (S): 32.07 g/mol
Oxygen (O): 16.00 g/mol
So, the molar mass of copper (II) sulfate (CuSO4) is:
63.55 g/mol + 32.07 g/mol + (16.00 g/mol x 4) = 159.61 g/mol
Now we can convert the given mass of copper (II) sulfate to moles as follows:
332.5 g / 159.61 g/mol = 2.08 moles
Step 2: Convert the given volume of the solution to liters.
The given volume is 750. mL. To convert mL to liters, we divide by 1000:
750. mL / 1000 = 0.75 liters
Step 3: Calculate the molarity.
Using the formula for molarity, we can substitute in the values we found:
Molarity = 2.08 moles / 0.75 liters = 2.77 M
Therefore, the molarity of the solution containing 750. mL of a solution containing 332.5 g of copper (II) sulfate is 2.77 M.
To find the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters). In this case, the amount of solute is given in grams, so we need to convert it to moles.
The molar mass of copper (II) sulfate (CuSO4) can be calculated by adding up the atomic masses of its individual elements:
Molar mass of Cu = 63.55 g/mol
Molar mass of S = 32.07 g/mol
Molar mass of O = 16.00 g/mol
Hence, the molar mass of CuSO4 = (1 * 63.55) + (1 * 32.07) + (4 * 16.00) = 159.61 g/mol.
Now, let's convert the amount of solute into moles:
332.5 g of CuSO4 × (1 mol / 159.61 g) = 2.084 mol.
Next, we need to convert the volume of the solution from milliliters to liters:
750 mL = 750 / 1000 = 0.75 L.
Finally, plug the values into the formula for molarity:
Molarity (M) = moles of solute / volume of solution (in liters) = 2.084 mol / 0.75 L = 2.7787 M (rounded to four decimal places).
Therefore, the molarity of the solution is approximately 2.7787 M.