Posted by Grace on .
A line in space has the vector equation shown here. Fill in the blanks to find the position vector to the fixed point on the line that appears in the equation:
vector r=(5+(6/11)d)vector i + (3+(9/11)d)vector j + (7+(2/11)d)vector k
vector v= _____ vector i + _____ vector j + ____ vector k
Write the coordinates of the point on the line that is 11 units in the positive d-direction away from the fixed point in this problem.
What is the "positive d-direction"? d is not a direction, it is a parameter for r(d).
If d is a parameter, any point involving d is not fixed.
Is the fixed point 5i + 3j + 7k and you want r(11)?
Yeah, sorry about that. There's a diagram to it and I wasn't sure how else to explain it.
Is it just ((6/11), (9/11), (2/11)) ?