Posted by Grace on .
A line in space has the vector equation shown here. Fill in the blanks to find the position vector to the fixed point on the line that appears in the equation:
vector r=(5+(6/11)d)vector i + (3+(9/11)d)vector j + (7+(2/11)d)vector k
vector v= _____ vector i + _____ vector j + ____ vector k
Write the coordinates of the point on the line that is 11 units in the positive ddirection away from the fixed point in this problem.

Precalc 
Steve,
What is the "positive ddirection"? d is not a direction, it is a parameter for r(d).
If d is a parameter, any point involving d is not fixed.
Is the fixed point 5i + 3j + 7k and you want r(11)? 
Precalc 
Grace,
Yeah, sorry about that. There's a diagram to it and I wasn't sure how else to explain it.

Precalc 
Grace,
Is it just ((6/11), (9/11), (2/11)) ?