Posted by **Grace** on Wednesday, January 18, 2012 at 7:07pm.

A line in space has the vector equation shown here. Fill in the blanks to find the position vector to the fixed point on the line that appears in the equation:

vector r=(5+(6/11)d)vector i + (3+(9/11)d)vector j + (7+(2/11)d)vector k

vector v= _____ vector i + _____ vector j + ____ vector k

Write the coordinates of the point on the line that is 11 units in the positive d-direction away from the fixed point in this problem.

- Precalc -
**Steve**, Thursday, January 19, 2012 at 12:16am
What is the "positive d-direction"? d is not a direction, it is a parameter for r(d).

If d is a parameter, any point involving d is not fixed.

Is the fixed point 5i + 3j + 7k and you want r(11)?

- Precalc -
**Grace**, Thursday, January 19, 2012 at 12:20am
Yeah, sorry about that. There's a diagram to it and I wasn't sure how else to explain it.

- Precalc -
**Grace**, Thursday, January 19, 2012 at 12:31am
Is it just ((6/11), (9/11), (2/11)) ?

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