Posted by Grace on Wednesday, January 18, 2012 at 7:07pm.
A line in space has the vector equation shown here. Fill in the blanks to find the position vector to the fixed point on the line that appears in the equation:
vector r=(5+(6/11)d)vector i + (3+(9/11)d)vector j + (7+(2/11)d)vector k
vector v= _____ vector i + _____ vector j + ____ vector k
Write the coordinates of the point on the line that is 11 units in the positive ddirection away from the fixed point in this problem.

Precalc  Steve, Thursday, January 19, 2012 at 12:16am
What is the "positive ddirection"? d is not a direction, it is a parameter for r(d).
If d is a parameter, any point involving d is not fixed.
Is the fixed point 5i + 3j + 7k and you want r(11)?

Precalc  Grace, Thursday, January 19, 2012 at 12:20am
Yeah, sorry about that. There's a diagram to it and I wasn't sure how else to explain it.

Precalc  Grace, Thursday, January 19, 2012 at 12:31am
Is it just ((6/11), (9/11), (2/11)) ?
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