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posted by john Wednesday, January 18, 2012 at 6:59pm.

calculate the PH of [OH-] = 4.5×10−3 M Please show how you work this problem.

pOH = -log(OH^-) pOH = -log(4.5E-3) Then pH + pOH = pKw = 14 so pH = 14-pOH You should end up with 11.65

thank you

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