Posted by **kyle** on Wednesday, January 18, 2012 at 6:29pm.

A woman pushes a crate along the floor of a warehouse with a force of 31.9 N directed downward at an angle of 23.6° from the horizontal. If the crate has a mass of 11.9 kg and the coefficient of friction is 0.0975, find...

(a) the force of friction

b. (b) theacceleration

- physics -
**Henry**, Friday, January 20, 2012 at 5:10pm
Wc = mg = 11.9 kg * 9.8 N/kg = 116.6 N=

Weight of crate.

Fc = 116.6 N @ (0) Deg.=Force of crate.

Fp = 116.6*sin(0) = 0 = Force parallel to floor.

Fv = 116.6*cos(0) = 116.6 N. = Force

perpendicular to floor.

a. Ff = u*(Fv+31.9*sin23.6),

Ff = 0.0975*(116.6+12.77) = 12.61 N.

Fn = Fap - Fp - Ff,

Fn = 31.9*cos23.6 - 0 - 12.61=16.62 N.

= Net force.

b. a = Fn/m = 16.62 / 11.9 = 1.397.

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