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September 17, 2014

September 17, 2014

Posted by **Rass** on Wednesday, January 18, 2012 at 6:29pm.

r^2=4sin2theta

2. find the coefficient of x^5 in the expansion (x+2)(x+1)^8

- math 12th grade -
**Rass**, Wednesday, January 18, 2012 at 6:44pmAnyone please help

- math 12th grade -
**Steve**, Wednesday, January 18, 2012 at 11:53pmx^2 + y^2 = r^2

x = rcosθ

y = rsinθ

r^2 = 4 sin2θ

r^2 = 8sinθcosθ

r^2 = 8 * y/r * x/r

r^4 = 8xy

(x^2 + y^2)^2 - 8xy = 0

(x+1)^8 = x^8 + 8x^7 + 28x^6 + 56x^5 + 70x^4 + ...

(x+2)(x+1)^8 = ... + 70x^5 + ... + 112x^5 + ...

= ... + 182x^5 + ...

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