Posted by Kelly on .
A rocket is fired at a speed of 75.0 m/s from ground level, at an angle of 59.7° above the horizontal. The rocket is fired toward an 11.0 m high wall, which is located 28.5 m away. The rocket attains its launch speed in a negligibly short period of time, after which its engines shut down and the rocket coasts. By how much does the rocket clear the top of the wall?

physics 
Damon,
Horizontal problem:
u = 75 cos 59.7 = 37.8 m/s horizontal
t = 28.5/37.8 = .753 s
Vertical problem:
Vi = 75 sin 59.7 = 64.75 m/s initial
h = 64.75 t  4.9 t^2
= 48.8  2.8 = 46 meters high
so
46  11 = 35 meters