posted by Kelly .
A rocket is fired at a speed of 75.0 m/s from ground level, at an angle of 59.7° above the horizontal. The rocket is fired toward an 11.0 m high wall, which is located 28.5 m away. The rocket attains its launch speed in a negligibly short period of time, after which its engines shut down and the rocket coasts. By how much does the rocket clear the top of the wall?
u = 75 cos 59.7 = 37.8 m/s horizontal
t = 28.5/37.8 = .753 s
Vi = 75 sin 59.7 = 64.75 m/s initial
h = 64.75 t - 4.9 t^2
= 48.8 - 2.8 = 46 meters high
46 - 11 = 35 meters