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December 18, 2014

December 18, 2014

Posted by **Anonymous** on Wednesday, January 18, 2012 at 4:38pm.

- algebra -
**Reiny**, Wednesday, January 18, 2012 at 5:30pmx = 8√x

what about it?

Are we solving for x?

x^2 = 64x

x^2 - 64x = 0

x(x-64) = 0

x = 0 or x = 64

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