Posted by Jordan on Wednesday, January 18, 2012 at 3:49pm.
Find all the critical numbers for the following function.
F(x) = (16 - x^2)^(3/5)
- Calculus (Help please) - Damon, Wednesday, January 18, 2012 at 5:08pm
f' = (3/5)(16-x^2)^(-2/5)(-2x)
That is undefined when x = 4 or x = -4 and is zero when x = 0
- Calculus (Help please) - Reiny, Wednesday, January 18, 2012 at 5:13pm
f'(x) = (3/5)(16 - x^2)^(-2/5) (-2x)
= 0 for max/min of f(x)
-2x = 0
x = 0 , then y = 16^(3/5)
find f''(x) using the product rule
set that equal to zero to find any points of inflection
x-intercepts, let y = 0
(16-x^2)^(3/5) = 0
x^2 = 16
x = ± 4
y-intercept, let x = 0
y = 16^(3/5)
Answer this Question
- calculus - Please help!! *f(x)= x(x+6)^1/2 find two x intercepts. Then show that...
- calculus - Find all the critical numbers for the function f(x) = cube root of 9-...
- help please! - f(x)=x+1/x Find all critical numbers. Find where the function is ...
- Calculus - Consider the function f(x)=ln(x)/x^6. For this function there are two...
- Calculus - How do you find the critical numbers and the end points of this ...
- calculus - 9) Find all critical numbers of the function f(t)=9t^2/3+t^5/3
- Calculus - Find the critical numbers of the function g(t)=|5t-7| If you find g'(...
- calculus help please - Consider the function f(x)=2x+9x^–1.? For this function ...
- Calculus - 1. For the function f(x)=4x^3-30x^2+4: a) Find the critical numbers ...
- calculus - Consider the function f (x)=x1=5(x4). This function ...