Wednesday

July 30, 2014

July 30, 2014

Posted by **Jordan** on Wednesday, January 18, 2012 at 3:49pm.

F(x) = (16 - x^2)^(3/5)

- Calculus (Help please) -
**Damon**, Wednesday, January 18, 2012 at 5:08pmf' = (3/5)(16-x^2)^(-2/5)(-2x)

That is undefined when x = 4 or x = -4 and is zero when x = 0

- Calculus (Help please) -
**Reiny**, Wednesday, January 18, 2012 at 5:13pmf'(x) = (3/5)(16 - x^2)^(-2/5) (-2x)

= 0 for max/min of f(x)

-2x = 0

x = 0 , then y = 16^(3/5)

find f''(x) using the product rule

set that equal to zero to find any points of inflection

x-intercepts, let y = 0

(16-x^2)^(3/5) = 0

x^2 = 16

x = ± 4

y-intercept, let x = 0

y = 16^(3/5)

**Related Questions**

calculus - Please help!! *f(x)= x(x+6)^1/2 find two x intercepts. Then show that...

calculus - Find all the critical numbers for the function f(x) = cube root of 9-...

help please! - f(x)=x+1/x Find all critical numbers. Find where the function is ...

Calculus - How do you find the critical numbers and the end points of this ...

Calculus - Find the critical numbers of the function g(t)=|5t-7| If you find g'(...

calculus help please - Consider the function f(x)=2x+9x^–1.? For this function ...

Calculus - 1. For the function f(x)=4x^3-30x^2+4: a) Find the critical numbers ...

calculus - Consider the function f (x)=x1=5(x��4). This function ...

Calculus - If y= (x^2+20)/(x-4) Find all critical Numbers. After get f' i got ...

Calculus - Find the critical numbers of f, find the open intervals on which the ...