Posted by Jordan on Wednesday, January 18, 2012 at 3:49pm.
Find all the critical numbers for the following function.
F(x) = (16  x^2)^(3/5)

Calculus (Help please)  Damon, Wednesday, January 18, 2012 at 5:08pm
f' = (3/5)(16x^2)^(2/5)(2x)
That is undefined when x = 4 or x = 4 and is zero when x = 0

Calculus (Help please)  Reiny, Wednesday, January 18, 2012 at 5:13pm
f'(x) = (3/5)(16  x^2)^(2/5) (2x)
= 0 for max/min of f(x)
2x = 0
x = 0 , then y = 16^(3/5)
find f''(x) using the product rule
set that equal to zero to find any points of inflection
xintercepts, let y = 0
(16x^2)^(3/5) = 0
x^2 = 16
x = ± 4
yintercept, let x = 0
y = 16^(3/5)
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