Post a New Question


posted by .

A small ball is launched at an angle of 30.0 degrees about the horizontal. It reaches a maximum height of 2.5m with a respect to the launch position.
What is the initial velocity of the ball when its launched?
What is the range, defined as a horizontal distance traveled until it returns to his original height. (you can ignore air resistance)

  • Physics -

    Yf^2 = Yo^2 + 2g*h,
    Yo^2 = Yf^2 - 2g*h,
    Yo^2 = o - (-19.6)*2.5 = 960.4,
    Yo = 31 m/s = Ver. component of Vo.

    a. Vo = Yo/sinA = 31/sin30 = 62 m/s = Initial velocity.

    b. R = Vo^2*sin(2A)/g,
    R = (62)^2*sin60/9.8 = 339.7 m.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question