Posted by sarah on Wednesday, January 18, 2012 at 1:59pm.
x^4 < 16x^2
x^2(x^2 - 16) < 0
x^2 is always positive, so
x^2 < 16
so, for -4 < x < 4
x^4 < 16x^2
at x=0, x^4 = 16x^2, so 0 is excluded from the solution
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