Wednesday

April 23, 2014

April 23, 2014

Posted by **Amy** on Wednesday, January 18, 2012 at 12:59pm.

- physics -
**John**, Wednesday, January 18, 2012 at 2:06pmx = x(initial) + v(initial)t + 1/2 at^2

0 = 1.5 + 0 + 1/2 (-10)t^2

1.5 = 5 t^2

t = 0.55 seconds

v = v(initial) + at

v = 0 + (-10)(0.55)

v = -5.5 m/s (i.e. it will reach the ground at 5.5 m/s)

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