Posted by Jo on Wednesday, January 18, 2012 at 3:00am.
log 6[ (64x^3+1)/(4x+1) ] = 1
(64x^3+1)/(4x+1) = 6^1
(4x+1)(16x^2 - 4x + 1)/(4x+1) = 6
16x^2 - 4x - 5 = 0
x= (4 ± √336)/32
= (4 ± 4√21)/32
= (1 ± 21)/8
We have to reject the negative answer or else the log would be undefined
so
x = (1 + √21)/8
Related Questions
college algebra - Solve the exponential equation. Express your solutions in ...
Math - Solve the logarithmic equation. Express your solutions in exact form only...
Math - Exponential equation - Solve the exponential equation. Express your ...
Math - 2 - Solve the exponential equation. Express your solutions in exact form ...
precalculus - Solve the logarithmic equation. Express your solutions in exact ...
pre calculus - Solve the exponential equation Express you solutions in exact ...
calculus - Please help me solve this equation. log[2](3)+log[2](x)=log[2](5)+log...
algebra homework - please check my answers. Solve the logarithmic equation. Be ...
precalculus - solve the exponential equation express in exact form only show all...
college algebra - solve the following logarithmic equation. 1. 2log(lower2) (x-2...
For Further Reading
