Tuesday

July 29, 2014

July 29, 2014

Posted by **Jo** on Wednesday, January 18, 2012 at 3:00am.

log base 6 (64x^3+1)-log base 6 (4x+1)=1

- College Algebra -
**Reiny**, Wednesday, January 18, 2012 at 8:41amlog

_{6}[ (64x^3+1)/(4x+1) ] = 1

(64x^3+1)/(4x+1) = 6^1

(4x+1)(16x^2 - 4x + 1)/(4x+1) = 6

16x^2 - 4x - 5 = 0

x= (4 ± √336)/32

= (4 ± 4√21)/32

= (1 ± 21)/8

We have to reject the negative answer or else the log would be undefined

so

x = (1 + √21)/8

**Related Questions**

Algebra 2 - -Explain the difference between log base b (mn) and ( log base b of ...

logarithms - Solve the logarithm equation. Express the solution in exact form ...

College Algebra - Solve the logarithmic equation for x. log(base 3)(x+6) - log(...

Advanced Functions/ Precalculus Log - 1. Evaluate 4^(log base4 64) + 10^(log100...

Math - Exponential equation - Solve the exponential equation. Express your ...

algebra homework - please check my answers. Solve the logarithmic equation. Be ...

college algebra - Solve the exponential equation. Express your solutions in ...

calculus - Please help me solve this equation. log[2](3)+log[2](x)=log[2](5)+log...

check! - here is the question: log5(x-4)= log7x solve for x. These are just base...

math(Please help) - 1) use the properties of logarithms to simplify the ...