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September 23, 2014

Homework Help: physics

Posted by Taylor on Tuesday, January 17, 2012 at 10:38pm.

A particle has a charge of +1.5 C and moves from point A to point B, a distance of 0.19 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA − EPEB = +5.50 10-4 J.
(a) Find the magnitude and direction of the electric force that acts on the particle.
magnitude N
direction

(b) Find the magnitude and direction of the electric field that the particle experiences.
magnitude N/C
direction

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