Posted by **becca** on Tuesday, January 17, 2012 at 9:40pm.

a two part canoe trip,the first part of the trip the canoist traveled 58 miles.Second part of the trip he traveled 18 miles at 5mph slower.the total time for trip was 4 hours.What was the speed of both parts of the trip?

- algebra -
**Reiny**, Tuesday, January 17, 2012 at 9:53pm
faster speed --- x mph

slower speed ---- x-5 mph

time at slower speed = 58/x

time at faster speed = 18/(x-5)

58/x + 18/(x-5) = 4

times x(x-5)

58(x-5) + 18x = 4x(x-5)

58x - 290 + 18x = 4x^2 - 20x

4x^2 -96x + 290 = 0

2x^2 - 48x + 145 = 0

x = (48 ± √1144)/4

= appr. 20.45 mph or 3.544 mph

if x = 20.45 , then x-5 = 15.45 mph

if x = 3.544 mph , then x-5 is a negative, so NO GOOD

Ridiculous answer!

I have done my share of canoeing, there is no way you can paddle a canoe at 20 mph!!!!

Absurd to canoe 76 miles in 4 hours.

- algebra -
**becca**, Tuesday, January 17, 2012 at 10:00pm
Thanks

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