Posted by Tay on .
a particle moves along the curve y= sqrt 1+x cubed. As it reaches the point (2,3) the ycorrdinate is increasing at a rate of 4cm/s. How fast is the xcoordinate of the point changing at that instant?

math 
bobpursley,
y= sqrt(1+x^3)
dy/dt= 1/2 * 1/sqrt(1+x^3)* 3x^2 dx/dt
dy/dt= 3x^2/2y * dx/dt
dx/dt= 2y dy/dt * 1/3x^2
you are given x, y, dy/dt, solve fod dx/dt.
check my work, I did it in a hurry 
math 
Tay,
hey thanks we are checking it now:)