Posted by **Anonymous** on Tuesday, January 17, 2012 at 8:10pm.

The weight of the block at rest on a frictionless table is 305 N. This block is attched by a string to another mass that hangs off a frictionless pulley. And the weight of the hanging block is 125 N. Ignoring all frictional effects and assuming the pulley to be massless, find the acceleration of the two blocks. Use g = 10 m/s^2 in all calculations

I do not know what formula to use please help.

- Physics -
**Damon**, Tuesday, January 17, 2012 at 8:15pm
F = 125 N

mass = (125+305)/10 = 43 kg

a = F/m = 125/43 = 2.9 m/s^2

- Physics -
**Omar**, Tuesday, May 22, 2012 at 4:20am
Sum of X forces = T = m1a = (30.5kg*a)

Sum of Y forces = 125N - T = m2a = (12.5kg*a)

125N - (30.5kg*a) = (12.5kg*a)

125N = 43kg*2a

2.85m/s^2 = 2a

1.425m/s^2 = a

## Answer this Question

## Related Questions

- phsyics - A cart of mass M1 = 6 kg is attached to a block of mass M2 = 3 kg by ...
- physics - A 4 kg wooden block rest on a table. the coefficient of friction ...
- physics - Masses 19 kg and 9 kg are connected by a light string that passes over...
- physics - Masses 19 kg and 9 kg are connected by a light string that passes over...
- Physics - A wooden block with mass 0.26{\rm kg} rests on a horizontal table, ...
- Physics - A block of mass 3.1 kg hangs vertically from a frictionless pulley of...
- Physics - A cart of mass M1 = 6 kg is attached to a block of mass M2 = 3 kg by a...
- physics - Block A has a mass of 4.1 kg, and it is on a frictionless surface. A ...
- Physics - A 5.0- kg concrete block rests on a level table. A 3.7- kg mass is ...
- Physics - A 5.7- kg concrete block rests on a level table. A 4.0- kg mass is ...

More Related Questions