A ball is thrown from the top of a 75-foot tower with a velocity of 32 feet per secon. Find the equation of the parabolic path.
Need for Module
To find the equation of the parabolic path of the ball, we can use the standard equation for the path of a projectile. This equation is given by:
y = -1/2gt^2 + vt + h
Where:
y = height of the ball above the ground (in this case, it will be 75 - h)
g = acceleration due to gravity (approximately 32 feet per second squared)
t = time since the ball was thrown
v = initial velocity of the ball (32 feet per second)
h = initial height of the ball above the ground (75 feet)
Substituting the given values into the equation, we have:
y = -16t^2 + 32t + 75
Thus, the equation of the parabolic path of the ball is y = -16t^2 + 32t + 75.