How many grams of a stock solution that is 87.0 percent H2SO4 by mass would be needed to make 200 grams of a 35.5 percent by mass solution? Show all of the work needed to solve this problem

%1 x grams = %2 x grams.

4425

To solve this problem, we can use the concept of mass percent and the equation:

mass of solute = (mass percent / 100) * mass of solution

Let's break down the given information:

1. We want to make 200 grams of a 35.5 percent H2SO4 solution.
2. The stock solution is 87.0 percent H2SO4 by mass.

Step 1: Calculate the mass of H2SO4 needed in the desired solution:
mass of H2SO4 = (35.5 / 100) * 200 grams
= 71 grams

Step 2: Determine the mass of the stock solution needed to obtain this amount of H2SO4.
Now, assuming that the stock solution contains only H2SO4 (for simplicity), we can set up the following equation:

(87.0 / 100) * mass of stock solution = 71 grams

To solve for the mass of the stock solution, divide both sides of the equation by the mass percent:

mass of stock solution = (71 grams) / (87.0 / 100)

Using the equation above, we can calculate:

mass of stock solution = (71 grams) / (0.87)
≈ 81.61 grams

Therefore, approximately 81.61 grams of the stock solution, which is 87.0 percent H2SO4 by mass, would be needed to make 200 grams of a 35.5 percent by mass solution.