posted by Yelena on .
A bakery has an average daily expense of $1350. The standard deviation is $150. The owner takes a sample of 50 bills, what is the probability the mean of his sample will be between $1200 and $1500?
how do i solve this
Z = (mean1 - mean2)/standard error of the mean (SEm)
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability between the Z scores.