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December 18, 2014

December 18, 2014

Posted by **Erica** on Tuesday, January 17, 2012 at 2:23am.

- Probability -
**Cecile**, Tuesday, January 17, 2012 at 2:28amRecall:

P(A∪B) = P(A) + P(B) - P(A∩B)

do we already given 3 of the unknown for this expression to find P(A∩B) ?

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