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August 1, 2014

August 1, 2014

Posted by **Anthony Clay** on Tuesday, January 17, 2012 at 12:02am.

Find the demand x for a price of (a) P=600?

So strange. Thx for help

- 10th Grade Pre-Calc -
**drwls**, Tuesday, January 17, 2012 at 5:50amDon't you mean

P = 5000[1 - 4/(4 + e^-.002x)]

?

If P = 600 ,

0.120 = [1 - 4/(4 + e^-.002x)]

4/(4 + e^-.002x)] = 0.88

4 + e^-.002x = 4.5454

e^-.002x = 0.5454

-0.002x = ln(0.5454) = -0.6061

x = 303

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