Posted by Sara on Monday, January 16, 2012 at 7:33pm.
First find the total age of all students from MM207(9062). Divide 9062 by the total students 244. The answer is 37.139 or 37. 95% confidence interval is 1.96. 37 + or - 1.96 =39 or 35. The professor's claim is quite reasonable.
Apparently Sharon has more data than is indicated on your post. Also I don't know how she found the SD.
95% = mean ± 1.96 SD
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