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November 23, 2014

November 23, 2014

Posted by **FEBIN** on Monday, January 16, 2012 at 7:19pm.

- arithmetic -
**Reiny**, Monday, January 16, 2012 at 11:11pmsum of n terms of 1st = (n/2)(10 + 36(n-1))

= (n/2)(36n - 26)

sum of 2n terms of 2nd = (2n/2)(72 + 5(2n-1))

= n(10n + 67)

(n/2)(36n - 26) = n(10n + 67)

divide by n, and multiply by 2

36n - 26 = 20n + 134

16n = 160

n = 10

check:

sum(10 for 1st) = 5(10 + 36(9)) = 1670

sum(20 for 2nd) = 10(72 + 19(5)) = 1670

all is good!

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