posted by Skye on .
how many kilojoules of heat are absorbed when 1.00 L of water is heated from 18C to 85C? density of water is 1.0 g/ml
q = mass x specific heat x (Tfinal-Tinitial)
how do u change L to grams?
1.00 L = 1,000 mL.
The density of water is 1.0 g/mL; therefore, 1,000 mL x 1.0 g/mL = 1,000 grams.
q=1000g x specific heat x 67C
what is the specific heat?
wait. is it 4.186 J/g*C?
so the answer is 280.462 KJ?
For water, the specific heat is 4.18 J/g*C. q, as you are calculating it, will be in joules. The problem asks for kJ so divide your answer by 1000 to convert to kJ.
1000g x 67c x 1.00cal/(g•c) x 1kj/1000cal